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copied!<p>Here's the correct way of doing it, keeping tabs on memory usage as well:</p> <pre><code>protected void onActivityResult(int requestCode, int resultCode, Intent data) { super.onActivityResult(requestCode, resultCode, data); if (resultCode == RESULT_OK) { Uri imageUri = data.getData(); Bitmap bitmap = getThumbnail(imageUri); } } public static Bitmap getThumbnail(Uri uri) throws FileNotFoundException, IOException{ InputStream input = this.getContentResolver().openInputStream(uri); BitmapFactory.Options onlyBoundsOptions = new BitmapFactory.Options(); onlyBoundsOptions.inJustDecodeBounds = true; onlyBoundsOptions.inDither=true;//optional onlyBoundsOptions.inPreferredConfig=Bitmap.Config.ARGB_8888;//optional BitmapFactory.decodeStream(input, null, onlyBoundsOptions); input.close(); if ((onlyBoundsOptions.outWidth == -1) || (onlyBoundsOptions.outHeight == -1)) { return null; } int originalSize = (onlyBoundsOptions.outHeight > onlyBoundsOptions.outWidth) ? onlyBoundsOptions.outHeight : onlyBoundsOptions.outWidth; double ratio = (originalSize > THUMBNAIL_SIZE) ? (originalSize / THUMBNAIL_SIZE) : 1.0; BitmapFactory.Options bitmapOptions = new BitmapFactory.Options(); bitmapOptions.inSampleSize = getPowerOfTwoForSampleRatio(ratio); bitmapOptions.inDither = true; //optional bitmapOptions.inPreferredConfig=Bitmap.Config.ARGB_8888;// input = this.getContentResolver().openInputStream(uri); Bitmap bitmap = BitmapFactory.decodeStream(input, null, bitmapOptions); input.close(); return bitmap; } private static int getPowerOfTwoForSampleRatio(double ratio){ int k = Integer.highestOneBit((int)Math.floor(ratio)); if(k==0) return 1; else return k; } </code></pre> <p>The getBitmap() call from Mark Ingram's post also calls the decodeStream(), so you don't lose any functionality.</p> <p>References:</p> <ul> <li><p><a href="https://stackoverflow.com/questions/4916159/android-get-thumbnail-of-image-on-sd-card-given-uri-of-original-image">Android: Get thumbnail of image on SD card, given Uri of original image</a></p></li> <li><p><a href="https://stackoverflow.com/questions/2220949/handling-large-bitmaps">Handling large Bitmaps</a></p></li> </ul>

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