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copied!<p><a href="http://download.oracle.com/javase/6/docs/api/index.html?java/util/regex/Pattern.html" rel="nofollow">Pattern</a> has a <code>String quote(String)</code> function that will help you for the first string and <a href="http://download.oracle.com/javase/6/docs/api/index.html?java/util/regex/Matcher.html" rel="nofollow">Matcher</a> has <code>String quoteReplacement(String)</code> for the second:</p> <pre><code>path = path.replaceFirst(java.util.regex.Pattern.quote("$SERVER"), java.util.regex.Matcher.quoteReplacement(System.getProperty("user.dir"))); </code></pre> <p>edit: the reason you have to escape anything is because the second string has the semantics of <a href="http://download.oracle.com/javase/6/docs/api/java/util/regex/Matcher.html#appendReplacement%28java.lang.StringBuffer,%20java.lang.String%29" rel="nofollow">Matcher.appendReplacement</a> which treats backslashes and dollars as escape next char and insert captured group resp. </p> <p>from the doc:</p> <blockquote> <p>Note that backslashes () and dollar signs ($) in the replacement string may cause the results to be different than if it were being treated as a literal replacement string. Dollar signs may be treated as references to captured subsequences as described above, and backslashes are used to escape literal characters in the replacement string.</p> </blockquote> <p>a more obvious solution is (be careful of the needed escaped with that backslash)</p> <pre><code> path = path.replaceFirst("\\$SERVER", System.getProperty("user.dir").replaceAll("\\\\","\\\\\\\\")); </code></pre>

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