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copied!<p>This depends on what you want to do, however, if you are primarily interested in the text between two bookmarks, then this is one of those cases where XmlDocument / XPath semantics are easier to use than LINQ to XML or the strongly-typed object model of the Open XML SDK V2. The semantics of the 'following::*' axis of XPath is what you want. The following example uses XmlDocument and XPath to print the names of the nodes between the start and end of a bookmark.</p> <pre><code>using System; using System.Collections.Generic; using System.IO; using System.Linq; using System.Text; using System.Xml; using DocumentFormat.OpenXml.Packaging; using DocumentFormat.OpenXml.Wordprocessing; class Program { public static XmlDocument GetXmlDocument(OpenXmlPart part) { XmlDocument xmlDoc = new XmlDocument(); using (Stream partStream = part.GetStream()) using (XmlReader partXmlReader = XmlReader.Create(partStream)) xmlDoc.Load(partXmlReader); return xmlDoc; } static void Main(string[] args) { using (WordprocessingDocument doc = WordprocessingDocument.Open("Test.docx", false)) { XmlDocument xmlDoc = GetXmlDocument(doc.MainDocumentPart); string wordNamespace = "http://schemas.openxmlformats.org/wordprocessingml/2006/main"; XmlNamespaceManager nsmgr = new XmlNamespaceManager(xmlDoc.NameTable); nsmgr.AddNamespace("w", wordNamespace); XmlElement bookmarkStart = (XmlElement)xmlDoc.SelectSingleNode("descendant::w:bookmarkStart[@w:id='0']", nsmgr); XmlNodeList nodesFollowing = bookmarkStart.SelectNodes("following::*", nsmgr); var nodesBetween = nodesFollowing .Cast<XmlNode>() .TakeWhile(n => { if (n.Name != "w:bookmarkEnd") return true; if (n.Attributes.Cast<XmlAttribute>().Any(a => a.Name == "w:id" && a.Value == "0")) return false; return true; }); foreach (XmlElement item in nodesBetween) { Console.WriteLine(item.Name); if (item.Name == "w:bookmarkStart" || item.Name == "w:bookmarkEnd") foreach (XmlAttribute att in item.Attributes) Console.WriteLine("{0}:{1}", att.Name, att.Value); } } } } </code></pre>

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