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copied!<p>I think you should be looking at the <code>VisualTree</code> for the Content, not your <code>LogicalTree</code>. </p> <p>Also, I couldn't really tell from your question above, but it sounded like you might be looking your ContentTemplate for your Content. If that is the case, it won't work because it's a template, so it doesn't actually contain the content. It's like looking at the Cookie Cutter to find the Cookie.</p> <p>And as a side note, I prefer to use DataTemplates than DataTriggers. You don't need a DataTemplateSelector either</p> <p>In my ParentViewModel I'll have a property like this:</p> <pre><code>private ViewModelBase _currentContent; public ViewModelBase CurrentContent { get {return _currentContent;} set { if (value != _currentContent) { _currentContent = value; OnPropertyChanged("CurrentContent"); } } } </code></pre> <p>and in the XAML for the ParentViewModel I would have something like</p> <pre><code><ContentControl Content="{Binding CurrentContent}" /> </code></pre> <p>Then I'd define my data templates for the different sub-viewmodel types</p> <pre><code><DataTemplate DataType="{x:Type local:SubViewModelA}"> <local:ViewA /> </DataTemplate> <DataTemplate DataType="{x:Type local:SubViewModelB}" /> <local:ViewB /> </DataTemplate> <DataTemplate DataType="{x:Type local:SubViewModelC}" /> <local:ViewC /> </DataTemplate> </code></pre> <p>To switch content, I'd change the master's <code>CurrentContent</code> property to whatever SubViewModel should be displayed</p>

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