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copied!<p>You are very likely doing a reference equals rather than a comparison equals. When using the capital lettered versions of the numeric types, you should use <code>one.equals(two)</code>.</p> <p>Ensure that the value of <code>tempPoint[2]</code> is <strong>exactly</strong> <code>2.0</code>. As a <code>double</code>, it's very possible that they are close, but not equal.</p> <p>You also might find using a foreach loop easier to follow:</p> <pre><code>private List<Double[]> bestPoints(List<Double[]> includedPoints) { List<Double[]> bestPoints = new ArrayList<Double[]>(); for (Double[] tempPoint : tempPoints) { if (tempPoint[2] == maxCount) { bestPoints.add(new Double[] { tempPoint[0], tempPoint[1] }); } } return bestPoints; } </code></pre> <p>If the values are always integers, then cast them before checking equality (e.g., <code>(long)tempPoint[2] == (long)maxCount</code>). If you want exact matches from <code>double</code>s, then continue what you are doing (after ensuring the proper type of equal check, dependent on maxCount), but if you want <em>near</em> matches (if decimals are a concern rather than predefined constants), then use an epsilon value:</p> <pre><code>public static boolean doubleEquals(double val1, double val2, double epsilon) { return Math.abs(val1 - val2) < epsilon; } public static boolean doubleEquals(double val1, double val2) { return doubleEquals(val1, val2, 1e-5); } </code></pre> <p>Obviously specify an epsilon value that makes sense for you.</p>

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