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copied!<p>You have several choices. The one that makes the most sense really depends on what you're trying to do.</p> <p><strong>Choice 1: make toyNumber a public member variable in a class</strong></p> <pre><code>class MyToy { public int toyNumber; } </code></pre> <p>then pass a reference to a MyToy to your method.</p> <pre><code>void play(MyToy toy){ System.out.println("Toy number in play " + toy.toyNumber); toy.toyNumber++; System.out.println("Toy number in play after increement " + toy.toyNumber); } </code></pre> <p><strong>Choice 2: return the value instead of pass by reference</strong></p> <pre><code>int play(int toyNumber){ System.out.println("Toy number in play " + toyNumber); toyNumber++; System.out.println("Toy number in play after increement " + toyNumber); return toyNumber } </code></pre> <p>This choice would require a small change to the callsite in main so that it reads, <code>toyNumber = temp.play(toyNumber);</code>.</p> <p><strong>Choice 3: make it a class or static variable</strong></p> <p>If the two functions are methods on the same class or class instance, you could convert toyNumber into a class member variable.</p> <p><strong>Choice 4: Create a single element array of type int and pass that</strong></p> <p>This is considered a hack, but is sometimes employed to return values from inline class invocations.</p> <pre><code>void play(int [] toyNumber){ System.out.println("Toy number in play " + toyNumber[0]); toyNumber[0]++; System.out.println("Toy number in play after increement " + toyNumber[0]); } </code></pre>

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