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POFind through which network device user is connected to internet
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  1. POFind through which network device user is connected to internet
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    copied!<p>Using the code below i will get all network interfaces wich are enabled and functional on the machine.</p> <pre><code>Private netIntrfc As NetworkInterface() = NetworkInterface.GetAllNetworkInterfaces() For i As Integer = 0 To netIntrfc.Length - 1 If netIntrfc(i).OperationalStatus = OperationalStatus.Up Then netDevicesList.Items.Add(netIntrfc(i).Name.ToString) End If Next </code></pre> <p>But my problem is how to get the <strong>default</strong> one, the one(<em>ethernet adapter</em>) through wich user is connected to internet?</p> <p>I need to change some settings of default(<em>through wich user is connected to internet</em>) adapter. settings i change through registry so i could sample add same settings for each network interface but that could cause problems and makes no point then :D</p> <p>can anyone help? Thank you! ;)</p> <p>EDITED:</p> <p>for now i have done like code below, so if this can help someone other... :) but if someone have batter solution or more reliable then send please</p> <pre><code>Dim u As UdpClient = New UdpClient(System.Net.Dns.GetHostName, 1) Dim localAddr As IPAddress = CType(u.Client.LocalEndPoint, IPEndPoint).Address Private netIntrfc As NetworkInterface() = NetworkInterface.GetAllNetworkInterfaces() For i As Integer = 0 To netIntrfc.Length - 1 If netIntrfc(i).OperationalStatus = OperationalStatus.Up Then For Each uni As NetworkInformation.UnicastIPAddressInformation In ipProps.UnicastAddresses If uni.Address.ToString = localAddr.ToString Then netDevicesList.Items.Add("DEFAULT: " &amp; netIntrfc(i).Name.ToString) DEFDEVID = netIntrfc(i).Id.ToString End If Next netDevicesList.Items.Add(netIntrfc(i).Name.ToString) End If Next </code></pre> <p><strong>Thanks <a href="https://stackoverflow.com/users/638404/thomas-li">Thomas-Li</a> and <a href="https://stackoverflow.com/questions/359596/identifying-active-network-interface-in-net">this post</a></strong></p>
 

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