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copied!<p>Another option, which is not quite the solution you wanted, but saves you using two separate regexes, is to use named groups, if your implementation supports it.</p> <p>Here is some C#:</p> <pre><code>var regex = new Regex(@"\=(?<Long>[0-9]+)\?|\+(?<Short>[0-9]+)\?"); string test1 = ";1234567890123456?+1234567890123456789012345123=9876543?"; string test2 = ";1234567890123456?+9876543?"; var match = regex.Match(test1); Console.WriteLine("Long: {0}", match.Groups["Long"]); // 9876543 Console.WriteLine("Short: {0}", match.Groups["Short"]); // blank match = regex.Match(test2); Console.WriteLine("Long: {0}", match.Groups["Long"]); // blank Console.WriteLine("Short: {0}", match.Groups["Short"]); // 9876543 </code></pre> <p>Basically just modify your regex to include the names, and then regex.Groups[GroupName] will either have a value or wont. You could even just use the Success property of the group to know which matched (match.Groups["Long"].Success).</p> <p><em>UPDATE:</em> You can get the group name out of the match, with the following code:</p> <pre><code>static void Main(string[] args) { var regex = new Regex(@"\=(?<Long>[0-9]+)\?|\+(?<Short>[0-9]+)\?"); string test1 = ";1234567890123456?+1234567890123456789012345123=9876543?"; string test2 = ";1234567890123456?+9876543?"; ShowGroupMatches(regex, test1); ShowGroupMatches(regex, test2); Console.ReadLine(); } private static void ShowGroupMatches(Regex regex, string testCase) { int i = 0; foreach (Group grp in regex.Match(testCase).Groups) { if (grp.Success && i != 0) { Console.WriteLine(regex.GroupNameFromNumber(i) + " : " + grp.Value); } i++; } } </code></pre> <p>I'm ignoring the 0th group, because that is always the entire match in .NET</p>

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