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copied!<p>I don't think anyone's clear on your requirement, but this is my best guess at addressing it... illustrating how to handle what you're calling the "dependency chain" in a template solution. If this doesn't help, but has any relevancy, then explaining it and the problems would help people help you. If you want to apply algorithmic loops over the <code>Foo<></code> objects I can illustrate how to do that....</p> <pre><code>#include <iostream> struct Abstract_Bar { virtual void f() const = 0; }; struct Bar1 : Abstract_Bar { void f() const { std::cout << "Bar1\n"; } }; struct Bar2 : Abstract_Bar { void f() const { std::cout << "Bar2\n"; } }; template <int N> struct Foo { typedef Foo<N - 1> Lower; typedef Foo<N + 1> Higher; void f() const { std::cout << "Foo<N>\n"; } Higher* higher_; }; template <> struct Foo<1> { typedef Foo<2> Higher; void f() const { std::cout << "Foo<1>\n"; } Higher* higher_; }; template <> struct Foo<4> { typedef Foo<3> Lower; typedef Abstract_Bar Higher; void f() const { std::cout << "Foo<4>\n"; } Higher* higher_; }; int main() { Foo<1> foo1; Foo<2> foo2; Foo<3> foo3; Foo<4> foo4; foo1.higher_ = &foo2; foo2.higher_ = &foo3; foo3.higher_ = &foo4; Bar1 bar1; foo4.higher_ = &bar1; foo1.f(); foo2.f(); foo3.f(); foo4.f(); foo1.higher_->f(); foo2.higher_->f(); foo3.higher_->f(); foo4.higher_->f(); // switch to another type of "Bar"... Bar2 bar2; foo4.higher_ = &bar2; foo4.higher_->f(); } </code></pre>

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