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copied!<p>Try this: </p> <pre><code>import re w = "TEMPLATES = ( ('index.html', 'home'), ('base.html', 'base'))" # find outer parens outer = re.compile("\((.+)\)") m = outer.search(w) inner_str = m.group(1) # find inner pairs innerre = re.compile("\('([^']+)', '([^']+)'\)") results = innerre.findall(inner_str) for x,y in results: print("%s <-> %s" % (x,y)) </code></pre> <p><strong>Output:</strong></p> <pre><code>index.html <-> home base.html <-> base </code></pre> <p><strong>Explanation:</strong></p> <p><code>outer</code> matches the first-starting group of parentheses using <code>\(</code> and <code>\)</code>; by default <code>search</code> finds the longest match, giving us the outermost <code>( )</code> pair. The match <code>m</code> contains exactly what's between those outer parentheses; its content corresponds to the <code>.+</code> bit of <code>outer</code>.</p> <p><code>innerre</code> matches exactly one of your <code>('a', 'b')</code> pairs, again using <code>\(</code> and <code>\)</code> to match the content parens in your input string, and using two groups inside the <code>' '</code> to match the strings inside of those single quotes.</p> <p>Then, we use <code>findall</code> (rather than <code>search</code> or <code>match</code>) to get all matches for <code>innerre</code> (rather than just one). At this point <code>results</code> is a list of pairs, as demonstrated by the print loop. </p> <p><strong>Update:</strong> To match the whole thing, you could try something like this:</p> <pre><code>rx = re.compile("^TEMPLATES = \(.+\)") rx.match(w) </code></pre>

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