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copied!<p>What we are having here is two different methods with individual type parameters each.</p> <pre><code>public abstract <T extends AnotherClass> void getAndParse(Args... args); </code></pre> <p>This is a method with a type parameter named T, and bounded by <code>AnotherClass</code>, meaning each subtype of <code>AnotherClass</code> is allowed as a type parameter.</p> <pre><code>public <SpecificClass> void getAndParse(Args... args) </code></pre> <p>This is a method with a type parameter named <code>SpecificClass</code>, bounded by <code>Object</code> (meaning each type is allowed as a type parameter). Do you really want this?</p> <p>Is the type parameter used inside <code>Args</code>? I think the problem would be there.</p> <hr> <p>Edit:</p> <p>The meaning of </p> <pre><code>public abstract <T extends AnotherClass> void getAndParse(T... args); </code></pre> <p>is that the <strong>caller</strong> of the method can decide with which type parameter he wants to call the method, as long as this is some subtype of <code>AnotherClass</code>. This means that in effect the method can be called with any objects of type <code>AnotherClass</code>.</p> <p>Since the caller can decide the type parameter, you can't in a subclass narrow down the parameter type to <code>SpecificClass</code> - this would not be an implementation of the method, but another method with same name (overloading).</p> <p>Maybe you want something like this:</p> <pre><code>public abstract class GetAndParse<T extends AnotherClass> { public SomeClass var; public abstract void getAndParse(T... args); } public class Implementor extends GetAndParse<SpecificClass> { // some field declarations // some method declarations @Override public void getAndParse(SpecificClass... args) { // method body making use of args } } </code></pre> <p>Now the <code>getAndParse</code> method implements the parent class' method.</p>

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