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POC program, pointer argument won't hold values
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copied!<p>Hi guys I'm sorry to bother you with this but I'm starting to loose it here.. I have recently started programming in C again and I have run into some kind bug that just I can't figure out.. My C program is(should be) an easy one, so it needs to do the following: An undefined number of natural elements is read form the keyboard until a 0 is read. After that it has to compute the product of all elements and compute the number of 0-s on the end of that result..</p> <pre><code>int input(int* v) { int n = 0; do { n = n + 1; v = (int*) realloc(v,n*sizeof(int)); printf("Enter number %d: ",n); scanf("%d",&v[n-1]); } while(v[n-1] != 0); n--; return n; } int tZeros(int* v, int eNb) { int i; int val = 1; for(i = 0; i < eNb; i++) { val = val * v[i]; } i=0; while(val % 10 == 0) { i++; } return i; } int main (int argc, char** argv) { int* v = NULL; int eNb = input(&(*v)); if(eNb>0) { int zeros = tZeros(v, eNb); printf("The number of ending zeros in the product of the given numbers is: %d",zeros); } else { printf("No elements to do computations with!\n"); } free(v); return 0; } </code></pre> <p>The input function should return two things: The number of elements and the actual elements in the dynamic array.. But after the input function runs the values entered there are all lost.. I pass the argument into input as a pointer so it should change the values at the correct addresses right?</p> <p>All suggestions are welcome! Thnx!</p> <p>P.s. I think the problem is with my array v.. after exiting the input function it looses all values..</p>

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