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copied!<p>Here's something that will do what you want, but the only thing is that it will <strong>not</strong> print out the matched word, instead just prints out the line matched, the file name, and the line number. However, if you use <code>--color=auto</code> on grep, it will highlight the matched words using whatever you have set in <code>${GREP_COLOR}</code>, the default is red.</p> <pre><code>cat files.txt | xargs grep -nf words.txt --color=auto </code></pre> <p>This command will dump all contents of <code>files.txt</code>, line by line, and it will pipe the file names to grep, which will search the file for every word that matches in <code>words.txt</code>. Similar to <code>files.txt</code>, <code>words.txt</code> should be all the search terms you want delimited by new-lines.</p> <p>If your grep was built with the perl regular expression engine, then, you can use Perl regular expressions if you pass the <code>-P</code> option to grep like so:</p> <pre><code>grep -Pnf words.txt --color=auto </code></pre> <p>Hope this helps.</p> <p>Update: At first, I wasn't really sure what @Zeophlite was asking but after he posted his example, I see what he wanted. Here's a python implementation of what he wants to do:</p> <pre><code>from contextlib import nested def search_file(line_num, filename): with nested(open(filename), open('words.txt')) as managers: open_filename, word_file = managers for line in open_filename: for wordfile_line_number, word in enumerate(word_file, 1): if word.strip() in line: print "%s => %s" % (line_num, wordfile_line_number) with open('files.txt') as filenames_file: for filenames_line_number, fname in enumerate(filenames_file, 1): search_file(filenames_line_number, fname.strip()) </code></pre>

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