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POProblem of Logic in Addressbook, should have no blank entries or same entry... Please Help
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  1. POProblem of Logic in Addressbook, should have no blank entries or same entry... Please Help
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    copied!<p>hope you can help me coding.</p> <p>What i need to do: 1.) I should not allow user to have a blank entry.. I should prompt them like "No name inputted!" 2.) I should not allow user to input same entry..</p> <p>I have no Idea how to code i, please help.</p> <p>Here's my complete code:</p> <p>public class AddressBook {</p> <pre><code>private AddressBookEntry entry[]; private int counter; private String SName; private int notfound=0; public static void main(String[] args) { AddressBook a = new AddressBook(); a.entry = new AddressBookEntry[100]; int option = 0; while (option != 5) { String content = "Choose an Option\n\n" + "[1] Add an Entry\n" + "[2] Delete an Entry\n" + "[3] Update an Entry\n" + "[4] View all Entries\n" + "[5] View Specific Entry\n" + "[6] Exit"; option = Integer.parseInt(JOptionPane.showInputDialog(content)); switch (option) { case 1: a.addEntry(); break; case 2: a.deleteEntry(); break; case 3: a.editEntry(); break; case 4: a.viewAll(); break; case 5: a.searchEntry(); break; case 6: System.exit(1); break; default: JOptionPane.showMessageDialog(null, "Invalid Choice!"); } } } public void addEntry() { entry[counter] = new AddressBookEntry(); entry[counter].setName(JOptionPane.showInputDialog("Enter name: ")); entry[counter].setAdd(JOptionPane.showInputDialog("Enter add: ")); entry[counter].setPhoneNo(JOptionPane.showInputDialog("Enter Phone No.: ")); entry[counter].setEmail(JOptionPane.showInputDialog("Enter E-mail: ")); counter++; } public void viewAll() { String addText = " NAME\tADDRESS\tPHONE NO.\tE-MAIL ADD\n\n"; int nonNull = 0; for (int i = 0; i &lt; entry.length; i++) { if (entry[i] != null) { addText = addText + entry[i].getInfo() + "\n"; nonNull++; } if (nonNull == counter) { break; } } JOptionPane.showMessageDialog(null, new JTextArea(addText)); } public void searchEntry() { SName = JOptionPane.showInputDialog("Enter Name to find: "); searchMethod(); } public void searchMethod() { for (int i = 0; i &lt; counter; i++) { if (entry[i].getName().equals(SName)) { JOptionPane.showMessageDialog(null, entry[i].getInfo2()); notfound = 0; break; } else { notfound++; } } if (notfound != 0) { JOptionPane.showMessageDialog(null, "Name Not Found!"); } } public void editEntry() { int notfound = 0; SName = JOptionPane.showInputDialog("Enter Name to edit: "); for (int i = 0; i &lt; counter; i++) { if (entry[i].getName().equals(SName)) { entry[i] = new AddressBookEntry(); entry[i].setName(JOptionPane.showInputDialog("Enter new name: ")); entry[i].setAdd(JOptionPane.showInputDialog("Enter new add: ")); entry[i].setPhoneNo(JOptionPane.showInputDialog("Enter new Phone No.: ")); entry[i].setEmail(JOptionPane.showInputDialog("Enter new E-mail: ")); notfound = 0; break; } else { notfound++; } } if (notfound != 0) { JOptionPane.showMessageDialog(null, "Name Not Found!"); } } public void deleteEntry() { SName = JOptionPane.showInputDialog("Enter Name to delete: "); for (int i = 0; i &lt; counter; i++) { if (entry[i].getName().equals(SName)) { JOptionPane.showMessageDialog(null, "Found!"); entry[i] = null; break; } } } </code></pre> <p>}</p> <p>What happen to my code was it allows user to click "OK" even he doesn't enter any character yet.. and it also allows identical entry...</p> <p>Hope you can help me... i need it very soon and yet i still have no Idea what to add in my code... please help thanks a lot..</p>
 

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