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POProblem with Visual Studio 2008 Debugger
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copied!<p>I have a weird problem with Visual Studio 2008 in just one of my projects. When I set a break point on a line of code, it gets hit alright, but when I try to 'step over,' or whatever else that is supposed to pass over that break point and stop on the next line, the code gets executed and continues as if I hit F5. This occurs even if I have another break point on the line just after this one, and strangely, the second break point is ignored (sometimes).</p> <p>Anybody, any ideas?</p> <p><strong>UPDATED</strong></p> <p>Here is a sample code. But it seems that anywhere that I have a try...catch block in which an exception is thrown, I have this problem.</p> <p>In the following code sample "return (T)bFormatter.Deserialize(mStream)" throws an exception.</p> <pre><code>public static T LoadEncryptedObject<T>(string location) where T : class { if( string.IsNullOrEmpty(location) || !System.IO.File.Exists(location) ) return default(T); System.IO.FileStream fs = null; try { fs = new System.IO.FileStream(location, System.IO.FileMode.Open, System.IO.FileAccess.Read, System.IO.FileShare.ReadWrite); BinaryFormatter bFormatter = new BinaryFormatter(); byte[] encryptedBytes = new byte[fs.Length]; fs.Read(encryptedBytes, 0, encryptedBytes.Length); MemoryStream mStream = new MemoryStream(Cryptography.Decrypt(encryptedBytes)); return (T)bFormatter.Deserialize(mStream); } catch( SerializationException sx ) { System.Diagnostics.Debug.WriteLine(sx.Message); return default(T); } finally { if( fs != null ) fs.Close(); } } </code></pre>

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