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copied!<p>If Group is a custom data type you can overload the <code>+</code>, <code>-</code>, <code>*</code>, <code>/</code>, <code>=</code>, <code>==</code>, <code>!=</code> and subsequently <code>+=</code>, <code>-=</code>, <code>*=</code>, and <code>/=</code> operators as shown here: <a href="http://msdn.microsoft.com/en-us/library/aa288467%28v=vs.71%29.aspx" rel="nofollow">MSDN: Operator Overloading Tutorial</a></p> <p>If your data type is a native data type: <code>int</code> (<code>Int32</code>), <code>long</code>, <code>decimal</code>, <code>double</code>, or <code>float</code> you can do the operations you have. </p> <p>To output the summation of your numbers you can use:</p> <pre><code>String.Format("{0} + {1} = {2}", Group1, Group2, (Group1 + Group2)); </code></pre> <p>or</p> <pre><code>String.Format("{0} + {1} + {2} = {3}", Group1, Group2, Group3, (Group1 + Group2 + Group3)); </code></pre> <p>Finally if in those examples Group is a custom data type, you would also have to overload the <code>ToString()</code> method so that it can display properly.</p> <pre><code><bleepzter/> </code></pre> <p>OK, Part 2 - OO Algorithm Design?</p> <p>So lets say you have the following:</p> <pre><code>public class Set: List<float> { public Set():base(){} public static Set operator+(Set set1, Set set2) { Set result = new Set(); result.AddRange(set1.ToArray()); result.AddRange(set2.ToArray()); return result; } public float Sum { get { if( this.Count == 0 ) return 0F; return this.Sum(); } } public override string ToString() { string formatString = string.Empty; string result = string.Empty; for(int i=0; i<this.Count; i++) { formatString += "{" + i.ToString() + "} + "; } formatString = result.TrimEnd((" +").ToCharArray()); // remove the last "+ "; float[] values = this.ToArray(); result = String.Format(formatString, values); return String.Format("{0} = {1}", result, this.Sum); } } </code></pre> <p>The object Set will have a <code>Sum</code> property, as well as a <code>ToString()</code> method that will display the sum and all of its content.</p>

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