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copied!<p>Following code is a part of my article : <strong>Pointers and Arrays in C C++</strong></p> <p>You can check it out @ <a href="http://pointersandarrays.blogspot.com/" rel="nofollow">http://pointersandarrays.blogspot.com/</a></p> <p><strong>Pointers and 2D Arrays</strong></p> <p>Following code snippet illustrates how to declare and access a 2D array. Underneath 2D Array lies a single dimensional array. You will get be sure of this after playing with the following piece of code. </p> <p><strong>Code Snippet #4</strong></p> <pre><code> #include<iostream&rt; using namespace std; int main() { cout<< "Understanding Pointers and 2 D Arrays"<<endl; cout<< "----------------------\n"<<endl; //Declaration of a 2D Array. int tab[3][5]; //Total space required : 3*5 * sizeof(int) = 15 * sizeof(int) //Funda : Since the amount of required space is known by compiler, contiguous 15 memory cells are allocated here. //Hence the case is similar to a 1 D Array of size 15. Lets try this out! //Array initialization using array name for(int i=0; i<3;i++) for(int j=0; j<5;j++) tab[i][j]=i+2*j; //Print array using array name cout << "\nPrint array using array name ..."<<endl; for(int i=0; i<3;i++) { for(int j=0; j<5;j++) printf("%2d ",tab[i][j] ); printf("\n"); } //Print array using a pointer. Proof of 1 D array being allocated cout << "\nPrint array using a pointer. Proof of 1 D array being allocated ..." << endl; int *tptr; tptr = &tab[0][0]; // pointer tptr points at first element of the array. for(int i=0; i<15;i++) printf("%d ",*(tptr+i) ); tptr = &tab[0][0]; cout << "\nNotice that array is printed row by row in a linear fashion."<<endl; return 0; } </code></pre> <p><strong>Output #4:</strong> <code></p> <pre><code>Understanding Pointers and 2D Arrays Print array using array name ... 0 2 4 6 8 1 3 5 7 9 2 4 6 8 10 Print array using a pointer. Proof of 1 D array being allocated ... 0 2 4 6 8 1 3 5 7 9 2 4 6 8 10 Notice that array is printed row by row in a linear fashion. </code></pre> <p></code></p>

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