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POPython script as linux service/daemon
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copied!<p>Hallo,</p> <p>I'm trying to let a python script run as service (daemon) on (ubuntu) linux.</p> <p>On the web there exist several solutions like:</p> <p><a href="http://pypi.python.org/pypi/python-daemon/" rel="noreferrer">http://pypi.python.org/pypi/python-daemon/</a></p> <blockquote> <p>A well-behaved Unix daemon process is tricky to get right, but the required steps are much the same for every daemon program. A DaemonContext instance holds the behaviour and configured process environment for the program; use the instance as a context manager to enter a daemon state.</p> </blockquote> <p><a href="http://www.jejik.com/articles/2007/02/a_simple_unix_linux_daemon_in_python/" rel="noreferrer">http://www.jejik.com/articles/2007/02/a_simple_unix_linux_daemon_in_python/</a></p> <p>However as I want to integrate my python script specifically with ubuntu linux my solution is a combination with an init.d script</p> <pre><code>#!/bin/bash WORK_DIR="/var/lib/foo" DAEMON="/usr/bin/python" ARGS="/opt/foo/linux_service.py" PIDFILE="/var/run/foo.pid" USER="foo" case "$1" in start) echo "Starting server" mkdir -p "$WORK_DIR" /sbin/start-stop-daemon --start --pidfile $PIDFILE \ --user $USER --group $USER \ -b --make-pidfile \ --chuid $USER \ --exec $DAEMON $ARGS ;; stop) echo "Stopping server" /sbin/start-stop-daemon --stop --pidfile $PIDFILE --verbose ;; *) echo "Usage: /etc/init.d/$USER {start|stop}" exit 1 ;; esac exit 0 </code></pre> <p>and in python:</p> <pre><code>import signal import time import multiprocessing stop_event = multiprocessing.Event() def stop(signum, frame): stop_event.set() signal.signal(signal.SIGTERM, stop) if __name__ == '__main__': while not stop_event.is_set(): time.sleep(3) </code></pre> <p>My question now is if this approach is correct. Do I have to handle any additional signals? Will it be a "well-behaved Unix daemon process"?</p>

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