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copied!<p>[EDIT] I made a mistake earlier, because, to get the text, you need to use .getText().toString().</p> <p>Here is a full working example:</p> <pre><code>package com.psegina.passwordTest01; import android.app.Activity; import android.os.Bundle; import android.view.View; import android.view.View.OnClickListener; import android.widget.Button; import android.widget.EditText; import android.widget.LinearLayout; import android.widget.Toast; public class Main extends Activity implements OnClickListener { LinearLayout l; EditText user; EditText pwd; Button btn; @Override public void onCreate(Bundle savedInstanceState) { super.onCreate(savedInstanceState); l = new LinearLayout(this); user = new EditText(this); pwd = new EditText(this); btn = new Button(this); l.addView(user); l.addView(pwd); l.addView(btn); btn.setOnClickListener(this); setContentView(l); } public void onClick(View v){ String u = user.getText().toString(); String p = pwd.getText().toString(); if( u.equals( p ) ) Toast.makeText(getApplicationContext(), "Matches", Toast.LENGTH_SHORT).show(); else Toast.makeText(getApplicationContext(), user.getText()+" != "+pwd.getText(), Toast.LENGTH_SHORT).show(); } } </code></pre> <p>Original answer (Will not work because of the lack of toString())</p> <p>Try using .getText() instead of .toString().</p> <pre><code>if( passw1.getText() == passw2.getText() ) #do something </code></pre> <p>.toString() returns a String representation of the whole object, meaning it won't return the text you entered in the field (see for yourself by adding a Toast which will show the output of .toString())</p>

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