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copied!<p>This can be achieved using Expressions:</p> <pre><code>// requires object instance, but you can skip specifying T static string GetPropertyName<T>(Expression<Func<T>> exp) { return (((MemberExpression)(exp.Body)).Member).Name; } // requires explicit specification of both object type and property type static string GetPropertyName<TObject, TResult>(Expression<Func<TObject, TResult>> exp) { // extract property name return (((MemberExpression)(exp.Body)).Member).Name; } // requires explicit specification of object type static string GetPropertyName<TObject>(Expression<Func<TObject, object>> exp) { var body = exp.Body; var convertExpression = body as UnaryExpression; if(convertExpression != null) { if(convertExpression.NodeType != ExpressionType.Convert) { throw new ArgumentException("Invalid property expression.", "exp"); } body = convertExpression.Operand; } return ((MemberExpression)body).Member.Name; } </code></pre> <p>Usage:</p> <pre><code>var x = new ObjectType(); // note that in this case we don't need to specify types of x and Property1 var propName1 = GetPropertyName(() => x.Property1); // assumes Property2 is an int property var propName2 = GetPropertyName<ObjectType, int>(y => y.Property2); // requires only object type var propName3 = GetPropertyName<ObjectType>(y => y.Property3); </code></pre> <p><strong>Update:</strong> fixed <code>GetPropertyName<TObject>(Expression<Func<TObject, object>> exp)</code> for properties returning value types.</p>

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