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copied!<p>Since the answer in the linked duplicate is not that comprehensive, I'll give an example:</p> <pre><code>$dom = new DOMDocument; $dom->loadXml($html); // use loadHTML if its invalid (X)HTML // create the new element $newNode = $dom->createElement('div', 'this is new'); $newNode->setAttribute('id', 'new_div'); // fetch and replace the old element $oldNode = $dom->getElementById('old_div'); $oldNode->parentNode->replaceChild($newNode, $oldNode); // print xml echo $dom->saveXml($dom->documentElement); </code></pre> <hr> <p>Technically, you don't need XPath for this. However, it can happen that your version of libxml cannot do <code>getElementById</code> for non-validated documents (<a href="http://www.w3.org/TR/2005/REC-xml-id-20050909/REC-xml-id-20050909.xml" rel="noreferrer">id attributes are special in XML</a>). In that case, replace the call to <code>getElementById</code> with</p> <pre><code>$xp = new DOMXPath($dom); $oldNode = $xp->query('//div[@id="old_div"]')->item(0); </code></pre> <p><a href="http://codepad.org/EJ8e6QYk" rel="noreferrer">Demo on codepad</a></p> <hr> <p>To create a <code>$newNode</code> with child nodes without having to to create and append elements one by one, you can do</p> <pre><code>$newNode = $dom->createDocumentFragment(); $newNode->appendXML(' <div id="new_div"> <p>some other text</p> <p>some other text</p> <p>some other text</p> <p>some other text</p> </div> '); </code></pre>

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