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POCreating WindsorViewPageActivator
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  1. POCreating WindsorViewPageActivator
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    copied!<p>I was playing with new Asp net mvc 3 RC2. I have created a WindsorViewPageActivator class as follows</p> <pre><code>public class WindsorViewPageActivator : IViewPageActivator { object IViewPageActivator.Create(ControllerContext controllerContext, Type type) { return DependencyResolver.Current.GetService(type); } } </code></pre> <p>and then a WindsorDependencyResolver class</p> <pre><code>public class WindsorDependencyResolver : IDependencyResolver { private readonly IWindsorContainer container; public WindsorDependencyResolver(IWindsorContainer container) { this.container = container; } #region IDependencyResolver Members public object GetService(Type serviceType) { return Resolve(serviceType); } public IEnumerable&lt;object&gt; GetServices(Type serviceType) { return container.ResolveAll(serviceType).Cast&lt;object&gt;(); } public IEnumerable&lt;TService&gt; GetAllInstances&lt;TService&gt;() { return container.ResolveAll&lt;TService&gt;(); } public TService GetInstance&lt;TService&gt;() { return (TService)Resolve(typeof(TService)); } #endregion private object Resolve(Type serviceType) { try { return container.Resolve( serviceType); } catch (Exception ex) { return null; } } } </code></pre> <p>}</p> <p>Now I am doing in Global.asax something like this</p> <pre><code>container.Register(Component.For&lt;IControllerActivator&gt;().ImplementedBy&lt;WindsorControllerActivator&gt;()); container.Register(Component.For&lt;IViewPageActivator&gt;().ImplementedBy&lt;WindsorViewPageActivator&gt;()); container.Register(Component.For&lt;IControllerFactory&gt;().ImplementedBy&lt;DefaultControllerFactory&gt;()); DependencyResolver.SetResolver (new WindsorDependencyResolver(container)); </code></pre> <p>' Now I am getting the following error The view found at '~/Views/Account/LogOn.cshtml' was not created. Do I need to register each view page in windsor container If yes then how can I register each view. I am using Razor view engine. Thanks </p>
 

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