StackOverflow2013

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copied!<p>I faced the same situation, and here is the solution I came with. My AQGridViewCell have both a TTImageView and a UIImageView. I use the TTImageView to load the image, and when it's loaded, I pass it to the UIImageView which displays it.</p> <p>To do that, my AQGridViewCell subclass implements the TTImageViewDelegate protocol. In my PostGridViewCell.h, I have :</p> <pre><code>@interface PostGridViewCell : AQGridViewCell <TTImageViewDelegate> { @private TTImageView *ttImageView_; UIImageView *imageView_; } // @property here … @end </code></pre> <p>In my implementation file, in the initWithFrame:reuseIdentifier: method, I init both my ttImageView and my imageView, but I only add the imageView as a subview of my cell. And I set the ttImageView delegate property to self (so I can be notified when the image is loaded) :</p> <pre><code>- (id)initWithFrame:(CGRect)frame reuseIdentifier:(NSString *)aReuseIdentifier { if ((self = [super initWithFrame:frame reuseIdentifier:aReuseIdentifier])) { // init image ttImageView_ = [[TTImageView alloc] initWithFrame:CGRectZero]; ttImageView_.delegate = self; imageView_ = [[UIImageView alloc] initWithFrame:CGRectZero]; [self.contentView addSubview:imageView_]; // … } return self; } </code></pre> <p>When the TTImaveView has loaded the image, it calls the imageView:didLoadImage: method on the delegate (which is the PostGridViewCell). In my implementation file, I have this method :</p> <pre><code>- (void)imageView:(TTImageView*)imageView didLoadImage:(UIImage*)image { self.imageView.image = image; [self setNeedsLayout]; } </code></pre> <p>Does it help?<br> Cheers,<br> Thomas.</p>

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