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copied!<p>Yes as most people recommended the best way seems to have a worker thread reading from a queue. Some code snippets below</p> <pre><code> pthread_t insertThread = NULL; pthread_mutex_t insertConditionNewMutex = PTHREAD_MUTEX_INITIALIZER; pthread_mutex_t insertConditionDoneMutex = PTHREAD_MUTEX_INITIALIZER; pthread_cond_t insertConditionNew = PTHREAD_COND_INITIALIZER; pthread_cond_t insertConditionDone = PTHREAD_COND_INITIALIZER; //Thread for new incoming connection void * newBatchInsert() { for(each Word) { //Push It into the queue pthread_mutex_lock(&lexicon[newPendingWord->length - 1]->insertQueueMutex); lexicon[newPendingWord->length - 1]->insertQueue.push(newPendingWord); pthread_mutex_unlock(&lexicon[newPendingWord->length - 1]->insertQueueMutex); } //Send signal to worker Thread pthread_mutex_lock(&insertConditionNewMutex); pthread_cond_signal(&insertConditionNew); pthread_mutex_unlock(&insertConditionNewMutex); //Wait Until it's finished pthread_cond_wait(&insertConditionDone, &insertConditionDoneMutex); } //Worker thread void * insertWorker(void *) { while(1) { pthread_cond_wait(&insertConditionNew, &insertConditionNewMutex); for (int ii = 0; ii < maxWordLength; ++ii) { while (!lexicon[ii]->insertQueue.empty()) { queueNode * newPendingWord = lexicon[ii]->insertQueue.front(); lexicon[ii]->insert(newPendingWord->word); pthread_mutex_lock(&lexicon[ii]->insertQueueMutex); lexicon[ii]->insertQueue.pop(); pthread_mutex_unlock(&lexicon[ii]->insertQueueMutex); } } //Send signal that it's done pthread_mutex_lock(&insertConditionDoneMutex); pthread_cond_broadcast(&insertConditionDone); pthread_mutex_unlock(&insertConditionDoneMutex); } } int main(int argc, char * const argv[]) { pthread_create(&insertThread, NULL, &insertWorker, NULL); lexiconServer = new server(serverPort, (void *) newBatchInsert); return 0; } </code></pre>

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