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POWhat is a fast way to generate and draw video in WPF?
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  1. POWhat is a fast way to generate and draw video in WPF?
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    copied!<p>I am writing a video player to play back frames captured by our ASIC. They are in a custom format, and I have been provided with a function that decodes the ASIC states. The video can be any size from 640x480 to 2560x1200 (!!!). The output of each state cycle is a 16x16 blocks of pixels, which I have to get into a video on the screen.</p> <p>Every time the screen needs to be updated, I have the following information:</p> <ul> <li>Block width</li> <li>Block height</li> <li>X coordinate of block start</li> <li>Y coordinate of block start</li> <li>A 1-D array of RGB32 pixel color info</li> </ul> <p>Major limitations:</p> <ul> <li>.NET 3.5</li> <li>No unsafe code</li> </ul> <p>I spent this morning trying out a WriteableBitmap, and using it as a source for an Image, something like this:</p> <pre><code> private WriteableBitmap ImageSource; public MainWindow() { InitializeComponent(); ImageSource = new WriteableBitmap(FrameWidth, FrameHeight, 96, 96, PixelFormats.Bgr32, null); ImagePanel.Source = ImageSource; } private void DrawBox(byte Red, byte Green, byte Blue, int X, int Y) { int BoxWidth = 16; int BoxHeight = 16; int BytesPerPixel = ImageSource.Format.BitsPerPixel / 8; byte[] Pixels = new byte[BoxWidth * BoxHeight * BytesPerPixel]; for (int i = 0; i &lt; Pixels.Length; i += 4) { Pixels[i + 0] = Blue; Pixels[i + 1] = Green; Pixels[i + 2] = Red; Pixels[i + 3] = 0; } int Stride = BoxWidth * BytesPerPixel; Int32Rect DrawBox = new Int32Rect(X, Y, BoxWidth, BoxHeight); ImageSource.Lock(); ImageSource.WritePixels(DrawBox, Pixels, Stride, 0); ImageSource.Unlock(); } </code></pre> <p>It works, my video plays on the screen, but it is sloooooooow. Nowhere near real-time play speed. Is there a better way, besides procedurally generating a series of bitmaps, to do this that I'm not seeing? I've read something about D3Dimage, but it seems that's more for exporting a 3D scene to a bitmap. Suggestions here?</p>
 

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