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copied!<p>Depending on the framework you're using (if one at all), just create a view for the order. You could either do this on another page or by loading a form via ajax. Either way, the form would look something like this:</p> <pre><code><?php if(isset($_POST['submit']) && $_POST['submit'] == "Submit") { $database->update("orders",$_POST,$_POST['id']); } $order = $database->query( "select id, order_id, project_ref, supp_short_code, om_part_no, description, quantity, cost_of_items, cost_total from orders where id = ".$id); ?> <form method="post" action="<?php echo basename($_SERVER['PHP_SELF']); ?>"> <input type="text" name="id" value="<?php echo $order['id']; ?>"> <input type="text" name="order_id" value="<?php echo $order['order_id']; ?>"> <input type="text" name="project_ref" value="<?php echo $order['project_ref']; ?>"> <input type="text" name="supp_short_code" value="<?php echo $order['supp_short_code']; ?>"> <input type="text" name="om_part_no" value="<?php echo $order['om_part_no']; ?>"> <input type="text" name="description" value="<?php echo $order['description']; ?>"> <input type="text" name="quantity" value="<?php echo $order['quantity']; ?>"> <input type="text" name="cost_of_items" value="<?php echo $order['cost_of_items']; ?>"> <input type="text" name="cost_total" value="<?php echo $order['cost_total']; ?>"> <input type="submit" name="submit" value="Submit"> </form> </code></pre> <p>The code for the $database object is here:</p> <p><a href="http://www.jtgraphic.net/code/database-object/" rel="nofollow">http://www.jtgraphic.net/code/database-object/</a></p>

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