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copied!<p>there are a lot of misconceptions here: </p> <ul> <li><p>you can only start a specific instance of a thread once. but in your case, the for loop is looping over different instances of a thread, each instance being assigned to the variable <code>thread</code> in the loop, so there is no problem at all in calling the <code>start()</code> method over each thread. (you can think of it as if the variable <code>thread</code> is an alias of the <code>Thread()</code> object instantiated in your list)</p></li> <li><p><code>run()</code> is not the same as <code>join()</code>: calling <code>run()</code> performs as if you were programming sequentially. the <code>run()</code> method does not start a new thread, it simply execute the statements in in the method, as for any other function call. </p></li> <li><p><code>join()</code> does note start executing anything: it only waits for a thread to finish. in order for <code>join()</code> to work properly for a thread, you have to call <code>start()</code> on this thread first.</p></li> </ul> <p>additionally, you should not that you cannot restart a thread once it has finished execution: you have to recreate the thread object for it to be started again. one workaround to get this working is to call <code>Thread.__init__()</code> at the end of the <code>run()</code> method. however, i would not recommend doing this since this will disallow the use of the <code>join()</code> method to detect the end of execution of the thread.</p>

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