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copied!<p><strong>Edit 2</strong>: </p> <p><strong>This is probably the easiest way to implement it</strong>. I tested it, it works fine. You could generate a infinite number of strings.</p> <pre><code>public IEnumerable<string> GenerateStrings() { foreach(string character in Alphabet()) { yield return character; } foreach (string prefix in GenerateStrings()) { foreach(string suffix in Alphabet()) { yield return prefix + suffix; } } } public IEnumerable<string> Alphabet() { for(int i = 0; i < 26; i++) { yield return ((char)('A' + i)).ToString(); } } </code></pre> <hr> <p>Stuff I wrote before:</p> <p>You could also write a little recursive function which returns any string by a certain index. This may not be optimal performance wise, because there are some repetitive divisions, but it may be fast enough for your purpose. </p> <p>It is quite short and easy:</p> <pre><code>string GetString(int index) { if (index < 26) { return ((char)('A' + index)).ToString(); } return GetString(index / 26 - 1) + GetString(index % 26); } </code></pre> <p>usage (may also be put into another method:</p> <pre><code>List<string> strings = Enumerable.Range(0, 1000) .Select(x => GetString(x)) .ToList(); </code></pre> <p>This is working code, just wrote a test for it.</p> <hr> <p><strong>Edit:</strong> eg, the "full linq way" application of GetString:</p> <pre><code>public void IEnumerale<string> GenerateStrings() { int index = 0; // generate "infinit" number of values ... while (true) { // ignoring index == int.MaxValue yield return GetString(index++); } } List<string> strings = GenerateStrings().Take(1000).ToList(); </code></pre>

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