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POHow do I call a constructor on a generic type within a function of a base type without its own constructor?
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  1. POHow do I call a constructor on a generic type within a function of a base type without its own constructor?
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    copied!<p>I thought a great way to test my understanding of generic functions would be to create a function that would spit out a hex representation of a hash using one of the classes that inherits from HashAlgorithm. Since all of the HashAlgorithm classes offer ComputeHash, I thought this would be simple. When I construct such a function. though, I get an error because HashAlgorithm itself doesn't offer a constructor. I couldn't find any sort of interface or subclass of HashAlgorithm that does offer a constructor, either. If not all HashAlgorithm classes are required to support a constructor, is there some additional constraint I can put on a generic type to ensure a type offers an empty constructor or will I be forced to create an overload for each of the HashAlgorithm classes I know offer an empty constructor.</p> <p>Here is what I have so far (in its non-compiling state):</p> <pre><code>public static string GetHexHash&lt;HashAlgorithmToUse&gt;(Stream dataStreamToHash) where HashAlgorithmToUse : HashAlgorithm { StringBuilder Result = new StringBuilder(); byte[] ByteHash = (new HashAlgorithmToUse()).ComputeHash(dataStreamToHash); foreach (byte HashByte in ByteHash) { Result.Append(HashByte.ToString("X2")); } return Result.ToString(); } </code></pre> <p><strong>Edit</strong> Matt Hamilton's answer nailed it right away, simply making the generic constraint more complex: <code>where HashAlgorithmToUse : HashAlgorith, new()</code>. I didn't even realize I could have multiple constraints. I definitely have a way to go before I fully understand all I can do with Generics. I suppose you can make a very non-generic, generic function if you get too carried away with the constraints.</p>
 

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