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copied!<p>See when you check in your second code</p> <pre><code>if (last != c) { </code></pre> <p>You are not checking for all conditions.<code>last</code> could be equal to space, tab or new line. In all such cases it should not print new line. Lets call the set of these three special characters as <code>X</code>.</p> <p>Now when printing new line, you need to make sure that <code>last</code> character printed does not bring to set <code>X</code>. But you check that <code>last!=current</code>. Now current could be space, tab or new line. But it is only one value. It does not serve our need, our purpose.</p> <p>So instead replace it with</p> <pre><code> if (last != ' ' && last != '\n' && last != '\t' ) { </code></pre> <p>You can see the code here:</p> <pre><code>#include <stdio.h> #define IN 1 // inside a word #define OUT 0 // outside a word // program to print input one word per line, corrected bug if there was // more than one space between words to only print one \n int main(void) { int c, last, state; last = 0; // We need it to make sure that a newline is not printed in case first // char is space, tab or new line. state = OUT; while ((c = getchar()) != EOF) { if (c == ' ' || c == '\n' || c == '\t') { // if (last != c) if (last != ' ' && last != '\n' && last != '\t' && last != 0 ) { state = OUT; printf("\n"); } } else if (state == OUT) { state = IN; } if (state == IN) { putchar(c); } last = c; } return 0; } </code></pre> <p><strong>Edit</strong><br/> Fixed the bug paxdiablo pointed out in comments.</p>

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