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POHow to list an image sequence in an efficient way? Numercial sequence comparison in Python
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  1. POHow to list an image sequence in an efficient way? Numercial sequence comparison in Python
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    copied!<p>I have a directory of 9 images:</p> <pre> image_0001, image_0002, image_0003 image_0010, image_0011 image_0011-1, image_0011-2, image_0011-3 image_9999 </pre> <p>I would like to be able to list them in an efficient way, like this (4 entries for 9 images):</p> <pre> (image_000[1-3], image_00[10-11], image_0011-[1-3], image_9999) </pre> <p>Is there a way in python, to return a directory of images, in a short/clear way (without listing every file)?</p> <p>So, possibly something like this:</p> <p>list all images, sort numerically, create a list (counting each image in sequence from start). When an image is missing (create a new list), continue until original file list is finished. Now I should just have some lists that contain non broken sequences.</p> <p>I'm trying to make it easy to read/describe a list of numbers. If I had a sequence of 1000 consecutive files It could be clearly listed as file[0001-1000] rather than file['0001','0002','0003' etc...]</p> <p><strong>Edit1</strong>(based on suggestion): Given a flattened list, how would you derive the glob patterns?</p> <p><strong>Edit2</strong> I'm trying to break the problem down into smaller pieces. Here is an example of part of the solution: data1 works, data2 returns 0010 as 64, data3 (the realworld data) doesn't work:</p> <pre><code># Find runs of consecutive numbers using groupby. The key to the solution # is differencing with a range so that consecutive numbers all appear in # same group. from operator import itemgetter from itertools import * data1=[01,02,03,10,11,100,9999] data2=[0001,0002,0003,0010,0011,0100,9999] data3=['image_0001','image_0002','image_0003','image_0010','image_0011','image_0011-2','image_0011-3','image_0100','image_9999'] list1 = [] for k, g in groupby(enumerate(data1), lambda (i,x):i-x): list1.append(map(itemgetter(1), g)) print 'data1' print list1 list2 = [] for k, g in groupby(enumerate(data2), lambda (i,x):i-x): list2.append(map(itemgetter(1), g)) print '\ndata2' print list2 </code></pre> <p>returns:</p> <pre><code>data1 [[1, 2, 3], [10, 11], [100], [9999]] data2 [[1, 2, 3], [8, 9], [64], [9999]] </code></pre>
 

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