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copied!<p>If you're not interested in the character based data the text file is containing, just stream it "raw" as bytes.</p> <pre><code>InputStream input = new BufferedInputStream(new FileInputStream("C:/logs.txt")); byte[] buffer = new byte[8192]; try { for (int length = 0; (length = input.read(buffer)) != -1;) { System.out.write(buffer, 0, length); } } finally { input.close(); } </code></pre> <p>This saves the cost of unnecessarily massaging between bytes and characters and also scanning and splitting on newlines and appending them once again.</p> <p>As to the performance, you may find <a href="http://nadeausoftware.com/articles/2008/02/java_tip_how_read_files_quickly" rel="nofollow">this article</a> interesting. According the article, a <a href="http://download.oracle.com/javase/6/docs/api/java/nio/channels/FileChannel.html" rel="nofollow"><code>FileChannel</code></a> with a 256K byte array which is read through a wrapped <a href="http://download.oracle.com/javase/6/docs/api/java/nio/ByteBuffer.html" rel="nofollow"><code>ByteBuffer</code></a> and written directly from the byte array is the fastest way.</p> <pre><code>FileInputStream input = new FileInputStream("C:/logs.txt"); FileChannel channel = input.getChannel(); byte[] buffer = new byte[256 * 1024]; ByteBuffer byteBuffer = ByteBuffer.wrap(buffer); try { for (int length = 0; (length = channel.read(byteBuffer)) != -1;) { System.out.write(buffer, 0, length); byteBuffer.clear(); } } finally { input.close(); } </code></pre>

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