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copied!<p>There isn't a built-in way of doing this, unfortunately - but it's really easy to write an extension method to do it.</p> <p>It was in <a href="http://msmvps.com/blogs/jon_skeet/archive/2005/10/02/a-short-case-study-in-linq-efficiency.aspx" rel="nofollow noreferrer">one of my very first blog posts</a>, in fact... note that there's a better implementation in one of the comments. I'll move it into the body if I get time. </p> <p>EDIT: Okay, I have a slightly abbreviated version - it just returns the maximal element, using the given selector. No need to do a projection as well - do that once afterwards if you need to. Note that you could remove the constraint on <code>TValue</code> and use <code>Comparer<TValue>.Default</code> instead, or have an overload which allows the comparison to be specified as another parameter.</p> <pre><code>public static TSource MaxBy<TSource, TValue>(this IEnumerable<TSource> source, Func<TSource, TValue> selector) where TValue : IComparable<TValue> { TValue maxValue = default(TValue); TSource maxElement = default(TSource); bool gotAny = false; foreach (TSource sourceValue in source) { TValue value = selector(sourceValue); if (!gotAny || value.CompareTo(maxValue) > 0) { maxValue = value; maxElement = sourceValue; gotAny = true; } } if (!gotAny) { throw new InvalidOperationException("source is empty"); } return maxElement; } </code></pre> <p>Sample use: (note type inference):</p> <pre><code>string maxName = models.MaxBy(model => model.Name.Length).Name; </code></pre>

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