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copied!<blockquote> <p>Something mysterious gets passed to the statusWrapper.write when runModule gets executed, but it's blank. What am I doing wrong?</p> </blockquote> <p>It's nothing mysterious: <code>write</code> just receives each string that was written to <code>sys.stdout</code> (that is, your wrapper, in this case).</p> <p>The bug is probably that the wrapper calls <code>setText</code> only, <em>replacing</em> the widget's text on each write, instead of appending to it. You'll need to at least do something like:</p> <pre><code> def write(self, s): self.widget.setText(self.widget.text() + s) </code></pre> <p>(or whatever the more efficient way is of appending text to a QT widget).</p> <h2>Note:</h2> <p>A much better way to redirect <code>sys.stdout</code> is to use a context manager. <a href="http://www.python.org/dev/peps/pep-0343/" rel="nofollow" title="PEP 343 -- The "with" Statement">PEP 343</a> defines the following example:</p> <pre><code>from contextlib import contextmanager @contextmanager def stdout_redirected(new_stdout): save_stdout = sys.stdout sys.stdout = new_stdout try: yield None finally: sys.stdout = save_stdout </code></pre> <p>You would use it like:</p> <pre><code>class Worker(QtCore.QThread, object): def run(self): with stdout_redirected(StatusWrapper(widget)): self.runModule() </code></pre> <p>Besides being more readable, this context manager makes sure to restore sys.stdout if <code>runModule</code> raises an exception (which is important for your sanity :-).</p>

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