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copied!<p>Concatenation is (significantly) faster according to my machine. But stylistically, I'm willing to pay the price of substitution if performance is not critical. Well, and if I need formatting, there's no need to even ask the question... there's no option but to use interpolation/templating.</p> <pre><code>>>> import timeit >>> def so_q_sub(n): ... return "%s%s/%d" % (DOMAIN, QUESTIONS, n) ... >>> so_q_sub(1000) 'http://stackoverflow.com/questions/1000' >>> def so_q_cat(n): ... return DOMAIN + QUESTIONS + '/' + str(n) ... >>> so_q_cat(1000) 'http://stackoverflow.com/questions/1000' >>> t1 = timeit.Timer('so_q_sub(1000)','from __main__ import so_q_sub') >>> t2 = timeit.Timer('so_q_cat(1000)','from __main__ import so_q_cat') >>> t1.timeit(number=10000000) 12.166618871951641 >>> t2.timeit(number=10000000) 5.7813972166853773 >>> t1.timeit(number=1) 1.103492206766532e-05 >>> t2.timeit(number=1) 8.5206360154188587e-06 >>> def so_q_tmp(n): ... return "{d}{q}/{n}".format(d=DOMAIN,q=QUESTIONS,n=n) ... >>> so_q_tmp(1000) 'http://stackoverflow.com/questions/1000' >>> t3= timeit.Timer('so_q_tmp(1000)','from __main__ import so_q_tmp') >>> t3.timeit(number=10000000) 14.564135316080637 >>> def so_q_join(n): ... return ''.join([DOMAIN,QUESTIONS,'/',str(n)]) ... >>> so_q_join(1000) 'http://stackoverflow.com/questions/1000' >>> t4= timeit.Timer('so_q_join(1000)','from __main__ import so_q_join') >>> t4.timeit(number=10000000) 9.4431309007150048 </code></pre>

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