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POHow to add the binary of a int with the binary of a string
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  1. POHow to add the binary of a int with the binary of a string
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    copied!<p>Basically i want to be able to get a 32bit int and attach its binary to the binary of a string. E.g. (IM going to use 8bit instead of 32bit) i want 255 + hi 11111111 + 0110100001101001 = 111111110110100001101001 So the int holds its binary value,i dont care how it comes out i just want it to be able to send the data over a socket.</p> <p>(This is all over websockets and the new sec-websocket-key's to stop hacking, if anyone just knows how to do the websocket handshake that would be just as nice)</p> <p>Thankyou ! I have been trying on this for days and im not one to come to this type of website to get the answer</p> <h2>EDIT</h2> <p>Ive been ask to give more info so her is the full deal. I have connected to the user of a stream port, he has sent me headers now i need to reply to to complete the connection. The import data is</p> <p>Sec-WebSocket-Key1: 4 @1 46546xW%0l 1 5"Random string following rules"(i will call this sk1)</p> <p>Sec-WebSocket-Key2: 12998 5 Y3 1 .P00 "Random string following rules"(i will call this sk2)</p> <p>^n:ds[4U "Random string following rules"(i will call this sk3)</p> <p>1) int1 = compress the numbers into sk1 and divid them by the amount of spaces in sk1</p> <p>2) int2 = compress the numbers into sk2 and divid them by the amount of spaces in sk2</p> <p>3) fullapend = Add append the bytes of int2 to int1 then append the bytes in sk3</p> <p>4) Finally MD5 digest fullapend</p> <p>5) Send the final result to the host along with some other headers and if they match up the connection holds open</p> <p>That is everything that needs to happen and i have not got a clue how to do it</p> <h2>Finished !</h2> <p>Well basic both answers was right and i would like to apologise if i seemed a bit rude, i didnt know the \x was a (something) meaning binary. but that worked a treat. Once i have the finished function to connect send etc... i will post it on here and else where for anyone else thats stuck, again thankyou !</p>
 

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