StackOverflow2013

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copied!<p>Well there are few problems in your code, but basic problem is you need NSMutableString string, not NSString to make your code work.</p> <ol> <li><p>in init method, correct code to initialize is,</p> <p><code>someCommonString = [[NSMutableString alloc] initWithString:@"one "];</code></p></li> <li><p>You have to return the object (self) from init, otherwise it will not work, like this.</p> <p><code>return self;</code></p></li> <li><p>If you wanted to append the string, it should be NSMutableString, not NSString.</p> <p><code>[[self someCommonString] appendString:test1];</code></p> <p><code>[[self someCommonString] appendString:test2];</code></p> <p><code>[[self someCommonString] appendString:test3];</code></p></li> <li><p>In dealloc method, you call dealloc method of super, not release the super. So correct it it like this.</p> <p><code>[super dealloc];</code></p></li> <li><p>There is no need to release <code>test1</code> and <code>test3</code>, because they are <strong>autorelease</strong>.</p></li> </ol> <p>I have witten the correct code, try this out.</p> <pre><code>@interface myClass : NSObject { @private NSMutableString* someCommonString; } @property (retain, nonatomic) NSMutableString* someCommonString; - (void) doTheJob; @end @implementation myClass @synthesize someCommonString; - (id) init { self = [super init]; if(self) { someCommonString = [[NSMutableString alloc] initWithString:@"one "]; } return self; } - (NSString*) appendString:(NSString*) stringToAdd { NSString* result = [someCommonString stringByAppendingString: stringToAdd]; return result; } - (void) doTheJob { NSString* test1 = @"two "; NSString* test2 = [[NSString alloc] initWithString: @"three "]; NSString* test3 = [NSString stringWithFormat:@"four "]; [[self someCommonString] appendString:test1]; [[self someCommonString] appendString:test2]; [[self someCommonString] appendString:test3]; NSLog(@"%@", someCommonString); [test2 release]; } - (void) dealloc { [someCommonString release]; [super dealloc]; } @end </code></pre>

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