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copied!<p>You will want to wire your URL to the Django <a href="https://docs.djangoproject.com/en/1.4/ref/generic-views/#django-views-generic-create-update-create-object" rel="nofollow noreferrer">create_object generic view</a>, and pass it either "model" (the model you want to create) or "form_class" (a customized <a href="https://docs.djangoproject.com/en/1.1/topics/forms/modelforms/#topics-forms-modelforms" rel="nofollow noreferrer">ModelForm</a> class). There are a number of <a href="https://docs.djangoproject.com/en/1.4/ref/generic-views/#django-views-generic-create-update-create-object" rel="nofollow noreferrer">other arguments</a> you can also pass to override default behaviors.</p> <p>Sample URLconf for the simplest case:</p> <pre><code>from django.conf.urls.defaults import * from django.views.generic.create_update import create_object from my_products_app.models import Product urlpatterns = patterns('', url(r'^admin/products/add/$', create_object, {'model': Product})) </code></pre> <p>Your template will get the context variable "form", which you just need to wrap in a <form> tag and add a submit button. The simplest working template (by default should go in "my_products_app/product_form.html"):</p> <pre><code><form action="." method="POST"> {{ form }} <input type="submit" name="submit" value="add"> </form> </code></pre> <p>Note that your Product model must have a get_absolute_url method, or else you must pass in the post_save_redirect parameter to the view. Otherwise it won't know where to redirect to after save.</p>

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