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POgetting the name of the invoked function
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copied!<p>when using either the '.', '->' or '->*' operators is there any way of getting the name of the function invoked (or the name of the variable in the case of '->*' and everything goes.</p> <p><strong>EDIT:</strong> Just to clarify I'm not talking about reflection but more something in the line of '<strong>function</strong>' basically I want to create an overload of an operator (preferrably one of the three mentioned) which is aware of the right side of the operator</p> <p>What I'm trying to accomplish is basically a compile time transformation of</p> <pre><code>obj->Function(a,b); </code></pre> <p>to</p> <pre><code>obj->Map("Function")(a,b); //Where Map(string) returns a function pointer </code></pre> <p><strong>EDIT:</strong> Just to further clarify, The requirement is that the code will have to <em>look</em> like one of these three</p> <pre><code>obj.SomeMethod(args); obj->SomeMethod(args); obj->*SomeMethod(args); </code></pre> <p>any solution that fits that is acceptable as long as SomeMethod can be any valid identifier (I.e. any thing that can be used as a function name) and the solution will have to use SomeMethod as a lookup in a Map. The Map part is already implemented it's only the reinterpretation of what looks like a method call I seeking a solution to.</p> <p>if that (as I'm affraid) can't be done then any solution with a new "operator" syntax will be accepted. Such as obj __ SomeMethod(args); as long as the lookup is based on the RHS of the "operator"</p>

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