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POCalling a function from the main thread and making it work in parallel with a function in the main thread
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  1. POCalling a function from the main thread and making it work in parallel with a function in the main thread
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    copied!<p>I really need your help in my issue very quickly and it's too close to the previous issue. I want to call a function using thread from the main thread.</p> <p>for more explanaition, here is a sample from my code: // please look to the code begining from ( //------- ) </p> <pre><code> // this function is being called from the Form1 class Like this //(this.Load += new System.EventHandler(this.Form1_Load);) private void Form1_Load(object sender, EventArgs e) { Common.MainForm = this; ftpServerIP = "74.220.215.77/ASGAQuraan"; ftpUserID = "sanbouk@asgatech.com"; ftpPassword = "asga_root"; iStartConnection = true; iGetNarratorData = false; iGetNarratorsSuras = false; _isExpandedIndecies = new string[10]; refreshPhons = true; count = 0; _btnDownload2PC.Enabled = false; _btnDownload2Phone.Enabled = false; //-------------------------------------------------------------------------------------- //timer1.Tick() is a function which Gets Data rom Phone //Now, GetFromServer, and GetFromPC are 2 functions which i want to them // to work in paralel with Timer1.Tick() //So, Fincally i want all 3 function work together with no gabs Timer1.Enabled = true; Timer1.Start(); if (InvokeRequired) { Invoke(new GetFromServerHandler(GetFromServer)); } else { ServerQuranTreeView.Nodes.Clear(); GetFromServer(); GetFromPC(); } } </code></pre> <p>** NOTE: in GetFromServer and GetFromPC I will update on a Tree which is in the main thread Form1 (GUI) and when when I tried to use thread ( thread _t = new Thread(new ThreadStart(GetFromServer))) this error appears: " Action being performed on this control is being called from the wrong thread. Marshal to the correct thread using Control.Invoke or Control.BeginInvoke to perform this action. " **</p> <p>I hope that I explained my problem well.</p> <p>Thanks in advance.</p>
 

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