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copied!<p>Why can I not do this:</p> <pre><code>char* p = new char[10]; void SetString(char * const str) { p = str; } SetString("Hello"); </code></pre> <p>I have a const pointer to a char, why can I not assign the const pointer to another pointer?</p> <p>It just seems illogical, as by assigning it to another pointer, you are not essentially violating the const-ness of the char pointer. Or are you?</p> <p>EDIT: When I compile this it says "error C2440: '=' : cannot convert from 'char *const *__w64 ' to 'char *'"</p> <p>(I'm attempting to understand a concept from a book I'm reading. Just cannot get the code to compile.</p> <p>CODE:</p> <pre><code>int _tmain(int argc, _TCHAR* argv[]) { MyString *strg = new MyString(10); strg->SetString("Hello, "); MyString *secondstr = new MyString(7); secondstr->SetString("Tony"); strg->concat(*secondstr, *strg); } </code></pre> <p>CPP FILE:</p> <pre><code>#include "MyStringClass.h" #include <string.h> #include "stdafx.h" #include "MyStringClass.h" void MyString::concat(MyString& a, MyString& b) { len = a.len + b.len; s = new char[len + 1]; strcpy(s, a.s); strcat(s, b.s); delete [] s; } void MyString::SetString(char * const str) { s = str; } MyString::MyString(int n) { s = new char[n+1]; s[n+1] = '\0'; len = n; } </code></pre> <p>HEADER FILE:</p> <pre><code>#include <string.h> #include <stdio.h> class MyString { private: char* s; int len; public: MyString(int n = 80); void SetString (char * const str); void concat (MyString& a, MyString& b); }; </code></pre>

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