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POHow can I get my bash script to work?
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copied!<p>My bash script doesn't work the way I want it to:</p> <pre><code>#!/bin/bash total="0" count="0" #FILE="$1" This is the easier way for FILE in $* do # Start processing all processable files while read line do if [[ "$line" =~ ^Total ]]; then tmp=$(echo $line | cut -d':' -f2) count=$(expr $count + 1) total=$(expr $total + $tmp) fi done < $FILE done echo "The Total Is: $total" echo "$FILE" </code></pre> <p>Is there another way to modify this script so that it reads arguments into <code>$1</code> instead of <code>$FILE</code>? I've tried using a <code>while</code> loop:</p> <pre><code>while [ $1 != "" ] do .... done </code></pre> <p>Also when I implement that the code repeats itself. Is there a way to fix that as well?</p> <p>Another problem that I'm having is that when I have multiple files <code>hi*.txt</code> it gives me duplicates. Why? I have files like <code>hi1.txt</code> <code>hi1.txt~</code> but the tilde file is of 0 bytes, so my script shouldn't be finding anything.</p> <hr> <p>What i have is fine, but could be improved. I appreciate your awk suggestions but its currently beyond my level as a unix programmer. </p> <p>Strager: The files that my text editor generates automatically contain nothing..it is of 0 bytes..But yeah i went ahead and deleted them just to be sure. But no my script is in fact reading everything twice. I suppose its looping again when it really shouldnt. I've tried to silence that action with the exit commands..But wasnt successful.</p> <pre><code>while [ "$1" != "" ]; do # Code here # Next argument shift done </code></pre> <p>This code is pretty sweet, but I'm specifying all the possible commands at one time. Example: hi[145].txt If supplied would read all three files at once. Suppose the user enters hi*.txt; I then get all my hi files read twice and then added again.</p> <p>How can I code it so that it reads my files (just once) upon specification of hi*.txt? I really think that this is because of not having $1.</p>

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