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copied!<p>I agree with @Fosco. I want to explain a little bit more-</p> <p>There may be two cases- 1. You are doing raw php 2. You are coding on any php framework like CI or your own.</p> <p>and this will help to identify error field and change style to make better user response. Also last input data remain as it was.</p> <ol> <li><p>You are doing raw php In this case you can receive the input data in same file/page. I will do a common example later.</p></li> <li><p>You are coding on any php framework like CI or your own. In this case you load a view file to show the form page and you can pass data to view page/file when you load it.</p></li> </ol> <p>For both of above case you can do some coding like-</p> <pre><code>/* your input validation and verification goes here. where $error is generated too In addition add some error status in above section, you can do it in your $error array too. Also you store received data into $data here. index of $data should be similar as (corresponding) HTML input name. You can do it like below */ $error_stat = array(); //if the input field name is "email" and email input data raises any error then $error_stat['email'] = true; // same for name $error_stat['name'] = true; // and so on // now decide whether you will back to the form page or send the email and do other tasks if(count($error_stat)<= 0){ // send email // do aditional tasks } else{ // load the form again if its aframework or the form is in seperate file // off course send $error,$data and $error_stat to the form page/file } // now here is a code segment of form page <?php if(isset($error) && count($error)>0):?> <div id="error-msg"> <?php //display errors here ?> </div> <?php endif;?> <form .... > <input type="text" name="email" class="<?php echo (isset($error_stat['email'])?'error':'else'); ?>" value="<?php echo $data['email'];?>" />\  </code></pre>

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