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copied!<p>EDIT: Okay, time for a short but complete program. The basic answer is as before:</p> <ul> <li>Find the "open" generic method with Type.GetMethod</li> <li>Make it generic using MakeGenericMethod</li> <li>Invoke it with Invoke</li> </ul> <p>Here's some sample code. Note that I changed the query expression to dot notation - there's no point in using a query expression when you've basically just got a where clause.</p> <pre><code>using System; using System.Linq; using System.Reflection; namespace Interfaces { interface IFoo {} interface IBar {} interface IBaz {} } public class Test { public static void CallMe<T>() { Console.WriteLine("typeof(T): {0}", typeof(T)); } static void Main() { MethodInfo method = typeof(Test).GetMethod("CallMe"); var types = typeof(Test).Assembly.GetTypes() .Where(t => t.Namespace == "Interfaces"); foreach (Type type in types) { MethodInfo genericMethod = method.MakeGenericMethod(type); genericMethod.Invoke(null, null); // No target, no arguments } } } </code></pre> <p><strong>Original answer</strong></p> <p>Let's leave aside the obvious problems of calling a variable "interface" to start with.</p> <p>You have to call it by reflection. The point of generics is to put more type checking at <em>compile</em> time. You don't know what the type is at compile-time - therefore you've got to use generics.</p> <p>Get the generic method, and call MakeGenericMethod on it, then invoke it.</p> <p>Is your interface type itself actually generic? I ask because you're calling MakeGenericType on it, but not passing in any type arguments... Are you trying to call</p> <pre><code>Method<MyNamespace.Interface<string>>(); // (Or whatever instead of string) </code></pre> <p>or </p> <pre><code>Method<MyNamespace.Interface>(); </code></pre> <p>If it's the latter, you only need a call to MakeGenericMethod - not MakeGenericType.</p>

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