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copied!<p>im not very experienced, but im trying to answer it for myself, maybe it can help you.</p> <p>To the first part of your question, for a string like that id simply split the given string at the apropriate positions. most frameworks have classes to do this. in your case for example that would be ( ) - and =</p> <p>result:</p> <p>Default, (, 0, -, 100, ) , =, 20</p> <ol> <li>Default</li> <li>(</li> <li>0</li> <li>-</li> <li>100</li> <li>)</li> <li>=</li> <li>20</li> </ol> <p>youre values are always at the same index when you use a consistent stringformat. pick them, convert if needed and store in variables;</p> <p>assuming youre talking about object orientated programming i would do something like this in your case:</p> <p>create a class employee with name, and hourly-wages as instance variables. this class has also a method calculateWageForHours(int hours). the hourlywages could be stored in a dictionairy or sth simlilar - depending on your framework. You take the beginning-hour as key for the dict an the wagerate as value. you dont need the ending-hours since one rate consists until the next "stage" is reached.</p> <p>the method to calculate the wage could look sth like this:(there sure is a better way depending on the concrete situation)</p> <pre><code>calculateWageForHours(int hours) { for (int i = 0, i < dict.count - 1, i++) { if (hours < dict[i + 1].key /* the int-value for the hour */ -1) { float wage; for (int j = 0, j < i, j++) { wage += (dict[j + 1].key - 1) * dict[j].value; } wage += (hours - dict[i].key - 1) * dict[i].value; return wage; } return calculateWageForHours(dict.lastkey - 1) + (hours - dict.lastkey) * dict.lastkey.value; </code></pre> <p>The default-part could be set anywhere in your programm where you instanciate the employee-class. just write a method which creates the default dictionairy for the employee. (could also be done in the object-initialisation and you hand in the nessesairy arguments from your controller-class)</p>

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