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copied!<p><strong>This transformation</strong>:</p> <pre><code><xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform"> <xsl:output omit-xml-declaration="yes" indent="yes"/> <xsl:variable name="vZeroes" select="'00000000000000000000000000000000000000'"/> <xsl:template match="node()|@*"> <xsl:copy> <xsl:apply-templates select="node()|@*"/> </xsl:copy> </xsl:template> <xsl:template match="/*"> <xsl:copy> <xsl:apply-templates select="*"> <xsl:sort select= "concat(substring($vZeroes, 1, string-length($vZeroes) - string-length(@hexVal) ), translate(@hexVal,'abcdef','ABCDEF') ) "/> </xsl:apply-templates> </xsl:copy> </xsl:template> </xsl:stylesheet> </code></pre> <p><strong>when applied on this XML document:</strong></p> <pre><code><t> <x hexVal="0A"/> <x hexVal="0327FE"/> <x hexVal="ff5240"/> <x hexVal="1BA402"/> <x hexVal="C3A214"/> </t> </code></pre> <p><strong>produces the wanted, correct result:</strong></p> <pre><code><t> <x hexVal="0A"/> <x hexVal="0327FE"/> <x hexVal="1BA402"/> <x hexVal="C3A214"/> <x hexVal="ff5240"/> </t> </code></pre> <p><strong>Solution details</strong>:</p> <p>The only assumption this solution makes is that the maximum length of the hexadecimal sort keys is limited (say to 20). Then we are using a string of zeroes, longer than this maximum length. The <code>$vZeroes</code> variable holds this string of zeroes and is used in padding every sort key to the left with zeroes, so that all sort keys have the same length.</p>

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