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copied!<p>You can also render a PartialViewResult to a string, and then pass this string via JSON to your view, rendering it in your page using jQuery.</p> <p>You can see that in this post: <a href="http://www.atlanticbt.com/blog/asp-net-mvc-using-ajax-json-and-partialviews/" rel="noreferrer">http://www.atlanticbt.com/blog/asp-net-mvc-using-ajax-json-and-partialviews/</a>.</p> <p>I've created an extension to make it easier:</p> <pre><code>public static class MvcHelpers { public static string RenderPartialView(this Controller controller, string viewName, object model) { if (string.IsNullOrEmpty(viewName)) viewName = controller.ControllerContext.RouteData.GetRequiredString("action"); controller.ViewData.Model = model; using (var sw = new StringWriter()) { ViewEngineResult viewResult = ViewEngines.Engines.FindPartialView(controller.ControllerContext, viewName); var viewContext = new ViewContext(controller.ControllerContext, viewResult.View, controller.ViewData, controller.TempData, sw); viewResult.View.Render(viewContext, sw); return sw.GetStringBuilder().ToString(); } } } </code></pre> <p>In my controller I call it as follows:</p> <pre><code>const string msg = "Item succesfully updated!"; return new JsonResult { Data = new { success = true, message = msg, view = this.RenderPartialView("ProductItemForm", model) }, JsonRequestBehavior = JsonRequestBehavior.AllowGet }; </code></pre> <p>Where "this" is the controller in the case, "ProductItemForm" is my view and "model" is my productItem object :)</p> <p>Hope this helps ;)</p>

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