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copied!<p>Took the code above and fixed because it throws Internal Server Error 500. There are some problems with \r\n badly positioned and spaces etc. Applied the refactoring with memory stream, writing directly to the request stream. Here is the result:</p> <pre><code> public static void HttpUploadFile(string url, string file, string paramName, string contentType, NameValueCollection nvc) { log.Debug(string.Format("Uploading {0} to {1}", file, url)); string boundary = "---------------------------" + DateTime.Now.Ticks.ToString("x"); byte[] boundarybytes = System.Text.Encoding.ASCII.GetBytes("\r\n--" + boundary + "\r\n"); HttpWebRequest wr = (HttpWebRequest)WebRequest.Create(url); wr.ContentType = "multipart/form-data; boundary=" + boundary; wr.Method = "POST"; wr.KeepAlive = true; wr.Credentials = System.Net.CredentialCache.DefaultCredentials; Stream rs = wr.GetRequestStream(); string formdataTemplate = "Content-Disposition: form-data; name=\"{0}\"\r\n\r\n{1}"; foreach (string key in nvc.Keys) { rs.Write(boundarybytes, 0, boundarybytes.Length); string formitem = string.Format(formdataTemplate, key, nvc[key]); byte[] formitembytes = System.Text.Encoding.UTF8.GetBytes(formitem); rs.Write(formitembytes, 0, formitembytes.Length); } rs.Write(boundarybytes, 0, boundarybytes.Length); string headerTemplate = "Content-Disposition: form-data; name=\"{0}\"; filename=\"{1}\"\r\nContent-Type: {2}\r\n\r\n"; string header = string.Format(headerTemplate, paramName, file, contentType); byte[] headerbytes = System.Text.Encoding.UTF8.GetBytes(header); rs.Write(headerbytes, 0, headerbytes.Length); FileStream fileStream = new FileStream(file, FileMode.Open, FileAccess.Read); byte[] buffer = new byte[4096]; int bytesRead = 0; while ((bytesRead = fileStream.Read(buffer, 0, buffer.Length)) != 0) { rs.Write(buffer, 0, bytesRead); } fileStream.Close(); byte[] trailer = System.Text.Encoding.ASCII.GetBytes("\r\n--" + boundary + "--\r\n"); rs.Write(trailer, 0, trailer.Length); rs.Close(); WebResponse wresp = null; try { wresp = wr.GetResponse(); Stream stream2 = wresp.GetResponseStream(); StreamReader reader2 = new StreamReader(stream2); log.Debug(string.Format("File uploaded, server response is: {0}", reader2.ReadToEnd())); } catch(Exception ex) { log.Error("Error uploading file", ex); if(wresp != null) { wresp.Close(); wresp = null; } } finally { wr = null; } } </code></pre> <p>and sample usage:</p> <pre><code> NameValueCollection nvc = new NameValueCollection(); nvc.Add("id", "TTR"); nvc.Add("btn-submit-photo", "Upload"); HttpUploadFile("http://your.server.com/upload", @"C:\test\test.jpg", "file", "image/jpeg", nvc); </code></pre> <p>It could be extended to handle multiple files or just call it multiple times for each file. However it suits your needs.</p>

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