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copied!<blockquote> <p>And I have the following XSL:</p> <pre><code><xsl:template match="/"> <xsl:copy-of select="ancestor::criterion/> </xsl:template> </code></pre> <p>which produces nothing!</p> </blockquote> <p><strong>As it should!</strong></p> <pre><code>ancestor::criterion </code></pre> <p>is a relative expression, which means that it is evaluated off the current node (matched by the template). But the current node is the document node <code>/</code>.</p> <p>So, the above is equivalent to:</p> <pre><code>/ancestor::criterion </code></pre> <p>However, by definition the document node <code>/</code> has no parents (and that means no ancestors), so this XPath expression doesn't select any node.</p> <blockquote> <p>I expected it to produce:</p> <pre><code><file> <criteria> </criteria> </file> </code></pre> </blockquote> <p>What you probably wanted was:</p> <pre><code>//criterion/ancestor::* </code></pre> <p>or</p> <pre><code>//*[descendant::criterion] </code></pre> <p>The last two XPath expressions are equivalent and select all elements that have a <code>criterion</code> descendant.</p> <p><strong>Finally, to produce the output you wanted, here is one possible solution:</strong></p> <pre><code><xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform"> <xsl:output omit-xml-declaration="yes" indent="yes"/> <xsl:strip-space elements="*"/> <xsl:template match="node()|@*"> <xsl:copy> <xsl:apply-templates select="node()|@*"/> </xsl:copy> </xsl:template> <xsl:template match="root | criterion | format"/> </xsl:stylesheet> </code></pre> <p><strong>When this transformation is applied on the provided XML document, the wanted output is produced</strong>:</p> <pre><code><file> <criteria> </criteria> </file> </code></pre>

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