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copied!<pre><code> private static IEnumerable<string> Parse(string input) { const string partPattern = @"([A-Fa-f0-9]{1,4})"; string longPattern = string.Format(@"{0} (?:\:{0})*", partPattern); //Group 1 -> 2 string compactPattern = string.Format(@"{0} (?:\:{0})* \:\: {0} (?:\:{0})*", partPattern, RegexOptions.IgnorePatternWhitespace); //Groups 3 ->6 string completePattern = string.Format(@"^{0}$ | ^{1}$", longPattern, compactPattern); var match = Regex.Match(input, completePattern, RegexOptions.IgnorePatternWhitespace); if (match.Success) { if (match.Groups[1].Success) { yield return match.Groups[1].Value.PadLeft(4, '0'); for (int i = 0; i < match.Groups[2].Captures.Count; ++i) yield return match.Groups[2].Captures[i].Value.PadLeft(4, '0'); } else { var count = 6 - match.Groups[4].Captures.Count - match.Groups[6].Captures.Count; //First part yield return match.Groups[3].Value.PadLeft(4, '0'); for (int i = 0; i < match.Groups[4].Captures.Count; ++i) yield return match.Groups[4].Captures[i].Value.PadLeft(4, '0'); //:: block for (int i = 0; i < count; ++i) yield return "0000"; //Second part yield return match.Groups[5].Value.PadLeft(4, '0'); for (int i = 0; i < match.Groups[6].Captures.Count; ++i) yield return match.Groups[6].Captures[i].Value.PadLeft(4, '0'); } } else throw new Exception("No match"); } </code></pre> <p>Something like this should work. The basic idea is just to split the case of the address containing :: and the rest into two different patterns. I used the assumption that :: can never be at the beginning or end so if that doesn't hold you'll have to modify the patterns a bit.</p>

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